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Answer :

B::C::DSolution :

`% of C = (12)/(44) xx ("Weight of" CO_(2) xx 100)/("Weight of compound")` <br> `(12 xx 1.1 xx 100)/(44 xx 0.45) = 66.66%` <br> `% of H = (2)/(18) xx ("Weight of" H_(2) O xx 100)/("Weight of compound")` <br> `= (2 xx 0.3 xx 100)/(18 xx 0.45) = 7.4%` <br> `% of N = [100 - (66.66 + 7.4)] = 25.93%`